72x^2-18x=35x^2

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Solution for 72x^2-18x=35x^2 equation:



72x^2-18x=35x^2
We move all terms to the left:
72x^2-18x-(35x^2)=0
determiningTheFunctionDomain 72x^2-35x^2-18x=0
We add all the numbers together, and all the variables
37x^2-18x=0
a = 37; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·37·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*37}=\frac{0}{74} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*37}=\frac{36}{74} =18/37 $

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